Is there list syntax sugar "[:]" for dictionaries in Python 2.7?

Asked Jul 27 '17 at 14:39

Active Jul 27 '17 at 14:46

Viewed 192 times

We can do the following for lists:

>>> a = [1, 2, 3, 4, 5, 6]
>>> b = []
>>> id(a)
140093169968840
>>> id(b)
140093169868528
>>> b[:] = a
>>> b
[1, 2, 3, 4, 5, 6]
>>> id(b)
140093169868528

b retains memory reference

Is there a way to do the same for two dictionaries in Python 2.7?

>>> a = {'one' :1, 'two' :2}
>>> b = {}
>>> b[...] = a  # ?

UPDATE: The answer is "No, there's no syntax sugar for dictionaries." It's not a duplicate. I'm not looking for a way to do it, othere that using syntax sugar.

edited Jul 27 '17 at 14:46

asked Jul 27 '17 at 14:39

olekb

@Mel I do not see syntax sugar in those answers – olekb Jul 27 '17 at 14:44
2

That's because there isn't one, but just saying *"no"* doesn't tell you how to get anything done! – jonrsharpe Jul 27 '17 at 14:45
1

That's because there isn't any. `clear/update` is the equivalent. – Mark Tolonen Jul 27 '17 at 14:46
@MarkTolonen thanx – olekb Jul 27 '17 at 14:47
3

Slice syntax has a clear meaning in lists, *from index a to index b*. Within *unordered* dicts, that syntax makes no sense. – deceze Jul 27 '17 at 14:48

Is there list syntax sugar "[:]" for dictionaries in Python 2.7?

0 Answers0