Remove n number of dot(.) from String in Java

Question

I have the following string and I want to remove dynamic number of dot(.) at the end of the String.

"abc....."

Dot(.) can be more than one

String s1="abc...."; String replaceString=s1.replaceAll("\\.",""); System.out.println(replaceString); — Mehul Jariwala, Jul 28 '17 at 06:34

Riaan Nel · Accepted Answer · 2017-07-28T06:53:02.390

4

Try this. It uses a regular expression to replace all dots at the end of your string with empty strings.

yourString.replaceAll("\\.+$", "");

edited Jul 28 '17 at 06:53

answered Jul 28 '17 at 06:14

Riaan Nel

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11
18

Thanks you bro. Exactly what I want. – T8Z Jul 28 '17 at 06:16
maybe need double backslash? – Scary Wombat Jul 28 '17 at 06:19
1

It needs to be `"\\.+$"` – anon Jul 28 '17 at 06:21
Opps, you are correct – anon Jul 28 '17 at 06:22
i tried my approach (see my answer) and it seems to work faster than regex. any ideas why? here goes the code https://pastebin.com/5Q6Uf13U – dsncode Jul 28 '17 at 06:34
@ScaryWombat - Thanks, looks like it got lost when I copied and pasted from my IDE. Fixed. – Riaan Nel Jul 28 '17 at 06:53
I'm curious as to why my answer was downvoted. – Riaan Nel Jul 28 '17 at 06:54
1

*I'm curious as to why my answer was downvoted* Strange things happen when you post code that does not even compile, let alone test – Scary Wombat Jul 28 '17 at 06:55

anon · Answer 2 · 2017-07-28T06:30:09.877

3

Could do this to remove all .:

String a = "abc.....";
String new = a.replaceAll("[.]", "");

Remove just the trailing .'s:

String new = a.replaceAll("//.+$","");

Edit: Seeing the comment. To remove last n .'s

int dotsToRemove = 5; // whatever value n
String new = a.substring(0, s.length()-dotsToRemove);

edited Jul 28 '17 at 06:30

answered Jul 28 '17 at 06:10

anon

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17

I don't think they want to just remove all dots. They wanna receive some sort of user input indicating how many dots from the end to remove. – Suhail Purkar Jul 28 '17 at 06:11
what should happen to string like "abc...cba....". His question is not clear. – codingenious Jul 28 '17 at 06:13
That won't work - replaceAll() uses regular expressions, and '.' matches anything, so you end up with an empty string. – Riaan Nel Jul 28 '17 at 06:15

dsncode · Answer 3 · 2017-07-28T06:35:39.553

how about using this function? seems to work faster than regex

public static String trimPoints(String txt)
    {
        char[] cs = txt.toCharArray();
        int index =0;
        for(int x =cs.length-1;x>=0;x--)
        {
            if(cs[x]=='.')
                continue;
            else
                {
                index = x+1;
                break;
                }
        }

        return txt.substring(0,index);
    }

Remove n number of dot(.) from String in Java

3 Answers3