File's string dont match

Question

here's the problem: i have a file ,,file.txt''.It is compossed by 11 words. Good. Now i have the code :

with open('/root/file.txt', 'r') as f:
 data = f.readlines()
 print data[10]

It outputs :

Password

But when i enter :

if data[10] == 'Password':
 print 'yes'
else:
 print 'no'

It outputs:

no

Can i know why ?I alredy tried to do ,,str(data[10])" but i get the same output : no. How i can do to get the yes answere ?

try `data[10].strip()=="Password"`. readlines includes line terminator. — Jean-François Fabre, Jul 30 '17 at 15:01
see /questions/15513433/python-readline-string-literal-never-returns-true — Jean-François Fabre, Jul 30 '17 at 15:02
Also, see: https://stackoverflow.com/questions/15233340/getting-rid-of-n-when-using-readlines — Zailef, Jul 30 '17 at 15:03

fvidalmolina · Accepted Answer · 2017-07-30T15:18:01.933

1

with readlines() you get a list with each line as a member of the list, this include the \n (return line code).

Print the whole list to see what I am saying.

with open('/root/file.txt', 'r') as f:
 data = f.readlines()
print data

To avoid the \n use this code:

data[10].strip() == 'Password'

If you just need to print something if the word Password is in there, try this code:

if 'Password' in data[10]:
  print 'yes'

edited Jul 30 '17 at 15:18

answered Jul 30 '17 at 15:06

fvidalmolina

score -1 · Answer 2 · answered Jul 30 '17 at 15:30

-1

This happens because in file "password" is stored as "password\n"

answered Jul 30 '17 at 15:30

DIksha Ahuja

2 Answers2