How to remove phrase and then 2 characters following it?

Question

I have a string similar to the following

circles_b2_test_20130206_rem01_toy.jpg

I'd like it to look like

circles_b2_test_20130206_toy.jpg

How can I remove only the "rem01" phrase? The numbers after rem are always changing but I always want to remove "rem" + 2 characters.

Can you please show what you have tried already for this? – idjaw Aug 03 '17 at 01:27 — idjaw, Aug 03 '17 at 01:27

score 2 · Answer 1 · answered Aug 03 '17 at 01:35

2

A bit "hacky," but this should achieve what you're after if there are always 2 numbers after the rem

str = "circles_b2_test_20130206_rem01_toy.jpg"
idx = str.index("rem")
new_str = str[:idx] + str[idx+6:]

answered Aug 03 '17 at 01:35

Dor-Ron

Sebastián Palma · Accepted Answer · 2017-08-03T01:41:43.067

2

If it's rem + two characters then you can use rem.{2}.

If it's rem + two digits then you can use rem\d{2}.

Note if you want circles_b2_test_20130206_toy.jpg then you need to check the _ in front of 01, you could try with:

import re
file = 'circles_b2_test_20130206_rem01_toy.jpg'
re.sub(r'rem\d{2}_?', '', file)
# 'circles_b2_test_20130206_toy.jpg'

edited Aug 03 '17 at 01:41

answered Aug 03 '17 at 01:36

Sebastián Palma

I think you meant to pass `file` as the third argument – Dor-Ron Aug 03 '17 at 01:41
Yei, thanks @Dor-Ron – Sebastián Palma Aug 03 '17 at 01:41
It works! Thanks – franchyze923 Aug 04 '17 at 02:01

2 Answers2