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I need to package a configuration file within a jar. the configuration file is under the root of the jar file. However I got the following error:

Caused by: java.lang.IllegalArgumentException: URI is not hierarchical at java.io.File.(Unknown Source)

File url = new File(MyClass.class.getClassLoader().getResource("my.conf").toURI());
mattbasta
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user217631
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3 Answers3

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You should use getResourceAsStream() instead. If the file is embedded in your JAR the URI is most likely bundle:// URI

InputStream is = this.getClass().getResourceAsStream("my.conf");
Joachim Sauer
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Andrew T Finnell
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7

Why do you need a file? IF you need to read the config use 

Class.getResourceAsStream("/my.conf");

This will need only to be the file in the one folder with the root of your package( the same as in the root of the jar)

Joachim Sauer
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Vladimir Ivanov
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4

The file should be in the same package as the MyClass. I just realized you are creating a File object. Instead try using getResourceAsStream(). This is the right way if you want to read the contents from a classpath resource. Here is the example.

Aravind Yarram
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  • correction: the file was found, but since it's inside a jar, i got uri is not hierarchical error – user217631 Dec 28 '10 at 19:18
  • Following error should be shown "Exception in thread "main" java.lang.IllegalArgumentException: URI is not hierarchical" – hiropon Oct 02 '17 at 07:36