Parse error in PHP code unexpected T_VARIABLE

Question

I'm trying to run this code

<?php
$mysqli = new mysqli("localhost", "root", "", "localhost");

$res = $mysqli->query("SELECT id, email FROM users WHERE id = 1");
$row = $res->fetch_assoc();

printf("id = %s (%s)\n", $row['id'], gettype($row['id']));
printf("email = %s (%s)\n", $row['email'], gettype($row['email']));
?>

But it's returning parse error

Parse error: syntax error, unexpected '$mysqli' (T_VARIABLE) in D:\xampp\htdocs\index.php on line 4

Anyone know what it could be?

score 0 · Accepted Answer · answered Aug 04 '17 at 07:19

please try your code in this way,

<?php
$con=mysqli_connect("localhost","my_user","my_password","my_db");
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$sql="SELECT id, email FROM users WHERE id = 1";
$result=mysqli_query($con,$sql);


// Associative array
$row=mysqli_fetch_assoc($result);
printf("id = %s (%s)\n", $row['id'], gettype($row['id']));
printf("email = %s (%s)\n", $row['email'], gettype($row['email']));

// Free result set
mysqli_free_result($result);

mysqli_close($con);
?>

if its helpful for you @1uckyCat , can you upvote? – Muhammad Akber Khan Aug 13 '17 at 13:55 — Muhammad Akber Khan, Aug 13 '17 at 13:55

Parse error in PHP code unexpected T_VARIABLE

1 Answers1