I had made a program in c in Ubuntu using gcc-7.I had sambleb.out file which is executable.I want to copy that file using c programming. here is the program.
#include <stdio.h>
int main()
{
FILE *fp;
fp = fopen("sampleb.out","rb");
FILE *fpcp;
fpcp = fopen("cp-of-sampleb.out","wb");
char forcp;
while (1)
{
forcp = fgetc(fp);
if(forcp == EOF)
break;
fputc(forcp, fpcp);
}
fclose(fp);
fclose(fpcp);
}
when I compile the program and execute the it, I get segmentation fault.
$ a.out && chmod a+x cp-of-sampleb.out
$ ./cp-of-sampleb.out
Segmentation fault
here is the content of cp-of-sample.out
$ cat cp-of-sampleb.out
ELF>0@@@@8 @@@@@@��88@8@@@,, `` (
((`(`��TT@T@DDP�td@@44Q�tdR�td``��/lib64/ld-
linux-x86-64.so.2GNU GNUX�T3�O���t�R�b�Ss�F
$
libc.so.6printf__libc_start_main__gmon_start__GLIBC_2.2.5ui
3�`` `H�H�%
H��t�CH��
and content of sampleb.out
$ cat sampleb.out
ELF>0@@@@8 @@@@@@��88@8@@@,, `` (
((`(`��TT@T@DDP�td@@44Q�tdR�td``��/lib64/ld-
linux-x86-64.so.2GNU GNUX�T3�O���t�R�b�Ss�F
$
libc.so.6printf__libc_start_main__gmon_start__GLIBC_2.2.5ui
3�`` `H�H�%
H��t�CH���5
�%
@�%
h������%
h������%�
]�8`��D]�fD�8`UH��8`H��H��H��H��?
H�H��t�H��tU�8`H=8`H��t�H��t
]�8`��]�fD�=a
uUH���~����O
]�D��@f.�UH��]��UH�忸@�������]�f.�DAWAVA��AUATL�% UH�-
SI��I��L)�H�H���g���H��t
1��L��L��D��A��H��H9�u�H�[]A\A]A^A_Ðf.���H�H��how are you I am
fine this singale line is printed by multiline
printf;4�����0���P����0��������zRx
�����*zRx
�$h���0FJ
U
�?;*3$"DW���A�C
Dd`���eB�B�E �B(�H0�H8�M@r8A0A(B BB�����@�@
�@` `���o�@@�@ �@
?
`0�@� ���o`@���o���oX@(`@@GCC: (Ubuntu 7.1.0-
5ubuntu2~16.04) 7.1.08@T@t@�@�@@X@`@ �@
�@
�@
@0@�@�@@8@` `(`�``(`8`��
`@�@!
�@78`F `m@y`������(@���(`(���`�(`(8`8�08)8h� P�
(I hadn't posted last line cause they were to many).Thus I can see that my program is coping only first 7 lines.It will be very helpful if you tell me what is wrong??? I am still noob.