How to know how many element the string array include?

Asked Aug 05 '17 at 04:06

Active Aug 05 '17 at 04:22

Viewed 39 times

I have a code can printf all of the string element like

#include <stdio.h>
int main()
{
    char * c[]={"I love you.","I don't."};
    char **p = c;
    for(int i=0;i<2;i++) //I judge the number is 2 by my eyes
        printf("%s\n",*p++);
    return 0;
}

But I don't like that part that I just can know the number is 2 by my eyes.Is there any elegant method can know how many element the array c contain?A in-built function maybe name count is ecpected in this post.Such as count(c) can give me the 2.

edited Aug 05 '17 at 04:22

asked Aug 05 '17 at 04:06

yode

May be [this post](https://stackoverflow.com/questions/37538/how-do-i-determine-the-size-of-my-array-in-c) could help you – Imran Ali Aug 05 '17 at 04:10
`sizeof c/sizeof *c` is a good start. – chux - Reinstate Monica Aug 05 '17 at 04:13
@chux You method can apply to a `int` array.But in a string array,every element take up different space. – yode Aug 05 '17 at 04:14
2

@yode The elements of the array are *pointers* not *strings*. Pointers take up constant space. – John Coleman Aug 05 '17 at 04:16
2

@yode - for `char *c[]` that doesn't matter. `sizeof(c)` gives the size of an array of pointers, and `sizeof(*c)` gives the size of a pointer (i.e. a `char *`). The initialisation of those pointers doesn't affect that. – Peter Aug 05 '17 at 04:17
@yode Useful site: [declare c as array of pointer to char](https://cdecl.org/?q=char+*+c%5B%5D) – chux - Reinstate Monica Aug 05 '17 at 04:19

How to know how many element the string array include?

0 Answers0