Sending multiple data with jquery Ajax in php

Question

I'm unable to understand these answers Question1 Question2 Question3 so posting my question.
I'm sending an Ajax request in PHP file:

$(document).ready(function(){
    $(document).on('click','.show_more',function(){
        var ID = 10;
        var USERID =1;
        $('.show_more').hide();
        $('.loding').show();
        $.ajax({
            type:'POST',
            url:'/ajaxload.php',
            data:'id='+ID & 'user_id=' + USERID,
            success:function(html){
                $('#show_more_main'+ID).remove();
                $('.post_list').append(html);
            }
        }); 
    });
});

while receiving Ajax URL id is received successfully but user_id is not getting received

<?php 
if(isset($_POST["id"]) && ($_POST["user_id"]) && !empty($_POST["id"])){
    echo $_POST["id"];
    echo $_POST["user_id"];
} 
?>

thank you @dlmeetei for improve my questions – Brijesh Patel Aug 06 '17 at 10:29 — Brijesh Patel, Aug 06 '17 at 10:29

score 3 · Accepted Answer · edited Aug 06 '17 at 11:23

3

Replace :

data:'id='+ID & 'user_id=' + USERID,

with:

data: {id:ID, user_id:USERID}

so your code will look like this :

$(document).ready(function(){
    $(document).on('click','.show_more',function(){
        var ID = 10;
        var USERID =1;
        $('.show_more').hide();
        $('.loding').show();
        $.ajax({
            type:'POST',
            url:'/ajaxload.php',
            data: {id:ID, user_id:USERID},
            success:function(html){
                $('#show_more_main'+ID).remove();
                $('.post_list').append(html);
            }
        }); 
    });
});

edited Aug 06 '17 at 11:23

dlmeetei

9,905
3
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38

answered Aug 06 '17 at 05:24

yoeunes

2,927
2
15
26

you welcome @BrijeshPatel and thank as well for acceping the answer – yoeunes Aug 06 '17 at 10:39
when i send VARCHAR then it's not working like USERID = "us1"; data: {id:ID, user_id:USERID}, this line is right or where i'm missing some step – Brijesh Patel Nov 22 '17 at 07:19

score 0 · Answer 2 · answered Aug 06 '17 at 05:31

0

pass the data as javascript objects

data:{
  id:ID,
  user_id:USERID
}

answered Aug 06 '17 at 05:31

Nijeesh Joshy

1,426
13
24

when i send VARCHAR then it's not working like `USERID = "us1";` `data: {id:ID, user_id:USERID},` this line is right or where i'm missing some step please help – Brijesh Patel Nov 22 '17 at 08:25
Could you give a little more info about the problem? @Brijesh Patel – Nijeesh Joshy Nov 22 '17 at 12:37

Sending multiple data with jquery Ajax in php

2 Answers2