Getting number of repetitions in regex

Question

Say I have a regex of /\n(\d)+/.

Let's say I test it against some random text:

aaaaaaaaaa
5aaaaaaaaa
4707aaaaaa
aaaaaaaaaa
923aaaaaaa

Is there a way I can get the number of times \d was repeated for each match?

I ask this because I'm using regex to do a find and replace on Notepad++ and was hoping I could achieve this end-result:

aaaaaaaaaa
Xaaaaaaaaa
XXXXaaaaaa
aaaaaaaaaa
XXXaaaaaaa

So only replace the digits after newline and each? How about [`(?:\G|^)\d` with `X`](https://regex101.com/r/MfLzGW/1) — bobble bubble, Aug 06 '17 at 15:23
@bobblebubble Thank you that works! If you don't mind, could you explain how your regex works? — mozicid, Aug 06 '17 at 15:32
@mozicid `^` means "start of line", and `\G` means "end of last match" 'they're both *anchors*), so `(?:\G|^)` means "end of last match or start of a line" — Lucas Trzesniewski, Aug 06 '17 at 15:47
you're welcome @mozicid! also lucas explained. glad it helped :) — bobble bubble, Aug 06 '17 at 15:54

score 3 · Accepted Answer · answered Aug 06 '17 at 15:51

3

If you want to match each digit at ^ start of line, the \G anchor can be used to chain matches. It matches at start of the string or where the previous match ended.

(?:\G|^)\d

Replace with

See this demo at regex101

answered Aug 06 '17 at 15:51

bobble bubble

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Getting number of repetitions in regex

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