How to use `prepare(_ context: CGContext, with rendererContext: UIGraphicsRendererContext)`?

Question

Starting iOS 10, Apple documents this class function in UIKit:

class func prepare(_ context: CGContext, with rendererContext: UIGraphicsRendererContext)

However, I was not able to access prepare in Xcode 8.3.3:

// error: Type 'UIGraphicsRenderer' has no member 'prepare'
UIGraphicsRenderer.prepare(UIGraphicsGetCurrentContext()!, with: UIGraphicsRendererContext())

// error: Type 'UIGraphicsImageRenderer' has no member 'prepare'
UIGraphicsImageRenderer.prepare(UIGraphicsGetCurrentContext()!, with: UIGraphicsRendererContext())

You have to import ````import UIKit.UIGraphicsRendererSubclass````, the method is defined in this class. — Fabio Berger, Aug 08 '17 at 06:31

score 1 · Accepted Answer · answered Aug 08 '17 at 06:36

1

The function prepare is defined in UIGraphicsRendererSubclass You can import this class with callingimport UIKit.UIGraphicsRendererSubclass

answered Aug 08 '17 at 06:36

Fabio Berger

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How to use `prepare(_ context: CGContext, with rendererContext: UIGraphicsRendererContext)`?

1 Answers1