$_Session don't work, how to use it in a proper way?

Question

I got a big problem when I tryed to work directly with session...

/* session_start(); //already tried */
if (isset($_SESSION) == false)
{
  session_start();
  $_SESSION['PDO'] = new dataBase();
  $_SESSION['Debug'] = 'Inside the isset';  
}
else
{
  $_SESSION['Debug'] = 'Outside the isset';  
}

EDIT:

session_start();
if (!isset($_SESSION['PDO'])) // the session is new
{ 
  $dbObject = new dataBase(); // store the data into the session
  $_SESSION['PDO'] = $dbObject;
  echo 'I created a session and stored some data into it';
} 
else 
{ // there is data into the session
  var_export($_SESSION);
  echo 'I have some data in the session';  
}

The output is always "I created a session and stored some data into it"

I begin to think that the problem may come from my class

class dataBase
{
  var $connLink;

  var $SERVERNAME = "127.0.0.1";
  var $PORT = "3388";
  var $USERNAME = "root";
  var $PASSWORD = "";

  function __construct()
  {
    try 
    {
        $this->connLink = new PDO("mysql:host=$this->SERVERNAME;port=$this->PORT;dbname=mydb;charset=utf8", $this->USERNAME, $this->PASSWORD);
        $this->connLink->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    }
    catch (PDOException $e) 
    {
        echo 'Echec lors de la connexion : ' . $e->getMessage();
    }
  }
}

Thanks !

M A Siddiqui if I do that I'll never affect my $_SESSION['PDO'] = new dataBase(); ... — Alexandre Corvino, Aug 08 '17 at 12:33
on each page where you want to do anything with SESSION, `session_start();` needed on top of the page just after starting ` — Alive to die - Anant, Aug 08 '17 at 12:35
just for my personal culture, using session to store an instance of database object isn't a good way, right ? — Frankich, Aug 08 '17 at 12:38
Possible duplicate of [Check if PHP session has already started](https://stackoverflow.com/questions/6249707/check-if-php-session-has-already-started) — harveyslash, Aug 08 '17 at 12:38
I put my session_start at the top inside a And i tried to see if $_Session['PDO'] wasn't set, I set it, else i put an victory message. But I always set the $_Session['PDO'] when i submit or refresh :( — Alexandre Corvino, Aug 08 '17 at 12:44
Thank's harvey_slash i'm sure that it will help me later it's a nice type for instanciate it ! — Alexandre Corvino, Aug 08 '17 at 12:46

score 2 · Answer 1 · answered Aug 08 '17 at 12:39

2

before accessing $_SESSION you first need to initialise session using session_start(); on the top of the page

answered Aug 08 '17 at 12:39

Lalit Chaudhary

21
2

score 0 · Answer 2 · answered Aug 08 '17 at 12:46

0

The $_SESSION variable does not exist until session_start() is called. This function needs to be called on each page.

Here is what you need to do :

session_start(); // start the session

if (!isset($_SESSION['PDO'])) { // the session is new
  $_SESSION['PDO'] = new dataBase(); // store the data into the session
  echo 'I created a session and stored some data into it';
} else { // there is data into the session
  echo 'I have some data in the session';  
}

On the first call on the page, the session is started and the pdo data stored into it. Then on the next calls on this page, the session is loaded from the server storage and the pdo data is in the session

Please note that sessions will not work if you use php from the command line

answered Aug 08 '17 at 12:46

ᴄʀᴏᴢᴇᴛ

2,939
26
44

the first time you load the page you will go inside the `isset`. then if you reload it, it will go into the `else` – ᴄʀᴏᴢᴇᴛ Aug 08 '17 at 12:49
Mmmmh my output is always "I created a session and stored some data into it" with that code. I don't unset anything in my dataBase class, i still don't understand – Alexandre Corvino Aug 08 '17 at 12:52
add this just after the session_start : `echo session_id();` and check if the id is the same when you reload the page – ᴄʀᴏᴢᴇᴛ Aug 08 '17 at 12:54
Yes i go the same id when i reload or input – Alexandre Corvino Aug 08 '17 at 12:55

Frankich · Answer 3 · 2017-08-08T13:05:25.160

0

session_start();

if (!isset($_SESSION['PDO']))
{
  $_SESSION['PDO'] = new dataBase();
  $_SESSION['Debug'] = 'Inside the isset'; 
}
else
{
  $_SESSION['Debug'] = 'Outside the isset';  
}

you have something like this ?

EDIT :

if(!isset($_SESSION['test']))
{
    $obj = new stdClass();
    $_SESSION['test'] = $obj;
}
else{
    var_export($_SESSION);
}

try this then

edited Aug 08 '17 at 13:05

answered Aug 08 '17 at 12:47

Frankich

842
9
19

Except that I change the debug to 'Inside the isset' when i define the $_SESSION['PDO'] – Alexandre Corvino Aug 08 '17 at 12:50
When i assign the class to my $_SESSION, i can't register more data – Alexandre Corvino Aug 08 '17 at 13:17

score 0 · Answer 4 · answered Aug 08 '17 at 13:12

0

use session_start() before $_SESSION Click here for more details .....

answered Aug 08 '17 at 13:12

Er Sahaj Arora

852
8
13

Only sublime text with easyPhp – Alexandre Corvino Aug 08 '17 at 13:27
try this $session = new Session(); – Er Sahaj Arora Aug 08 '17 at 13:28
At the begining ? And what will become $_SESSION ? or you mean is that $_SESSION = new Session() – Alexandre Corvino Aug 08 '17 at 13:30

score 0 · Answer 5 · answered Aug 09 '17 at 13:54

0

Finally I decided to never create my object and to use it only by static function Like dataBase::connectDB(); etc ...

answered Aug 09 '17 at 13:54

Alexandre Corvino

199
1
3
16

$_Session don't work, how to use it in a proper way?

5 Answers5