Parsing JSON when nested or otherwise a bit more complicated than single values

Question

Here's the JSON:

{
    "firstName": "John",
    "lastName": "doe",
    "age": 26,
    "address": {
        "streetAddress": "123 Main street",
        "city": "Anytown",
        "postalCode": "12345"
    },
    "phoneNumbers": [
        {
            "type": "iPhone",
            "number": "123-456-8888"
        },
        {
            "type": "home",
            "number": "123-557-8910"
        }
    ]
}

The question is, in Java, how do you access the address fields? I tried things like address.city, but that didn't work:

String city = (String) jsonObject.get("address.streetAddress");
System.out.println(city);

Would appreciate any suggestions.

score 0 · Answer 1 · answered Aug 08 '17 at 20:43

0

You need to call getString on the address object that you get.

String city = jsonObject.getJSONObject("address").getString("streetAddress");

answered Aug 08 '17 at 20:43

mittmemo

2,062
3
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score 0 · Answer 2 · edited Aug 08 '17 at 22:23

{
    "firstName": "John",
    "lastName": "doe",
    "age": 26,
    "address": {
        "streetAddress": "123 Main street",
        "city": "Anytown",
        "postalCode": "12345"
    },
    "phoneNumbers": [
        {
            "type": "iPhone",
            "number": "123-456-8888"
        },
        {
            "type": "home",
            "number": "123-557-8910"
        }
    ]
}

first get your address.Address is an object.{} means object,[] means an array.

JSONObject addressObj = jsonObject.get("address");

now you have a reference to the address.

String addressStr = addressObj.get("streetAddress");
String cityStr = addressObj.get("city");
int cityInt = Integer.parseInt(addressObj.get("postalCode"));

If i don't wrong remember there should be getString("streetAddress") and getInteger("postalCode") to avoid parse issues.

score 0 · Answer 3 · edited Aug 08 '17 at 22:24

0

Apart from the given answers you should add a check to see if the address is not blank before checking city or else you will end up getting and exception. Here is updated example:

if( jsonObject.has("address"){
    JSONObject addressObj = jsonObject.get("address");

    if( addressObj.has("city"){
        String cityStr = addressObj.get("city");
    }
}

edited Aug 08 '17 at 22:24

Jason

11,744
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answered Aug 08 '17 at 21:16

Amit Mahajan

895
6
34

Parsing JSON when nested or otherwise a bit more complicated than single values

3 Answers3