kotlin android start new service

Question

By using the below code, I'm trying to start new service from a Broadcast receiver, but the service does not seem to start. What is the correct way to start a service in kotlin?

val intent = Intent(context, LocationService::class.java)
 if (context != null) {
      context.startService(intent)
 }

Make sure that `startService` returns non-null value, this will indicate that service was started. Keep in mind that `startService` is deprecated in Android O and will throw exception for `targetSdk 26`. — Miha_x64, Aug 09 '17 at 09:15

score 16 · Answer 1 · edited Nov 21 '17 at 07:19

16

try this

 val intent = Intent(context, LocationService::class.java)
 if (context != null) {
      context.startService(intent)
 }

And don't forget to register your service in manifest file

 <service  android:name="packageName.LocationService"/>

edited Nov 21 '17 at 07:19

Nigam Patro

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answered Aug 09 '17 at 08:53

AskNilesh

67,701
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163

score 5 · Answer 2 · answered Oct 30 '19 at 06:46

5

Use safe access compression in kotlin:

val intent = Intent(context, LocationService::class.java)
context?.startService(intent)

Also define your service in your manifest.

answered Oct 30 '19 at 06:46

Anice Jahanjoo

7,088
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score 1 · Answer 3 · answered Aug 09 '17 at 08:54

1

Put declaration of service in AndroidManifest.xml file
i.e <service android:name=".LocationService"/>

answered Aug 09 '17 at 08:54

mac229

4,319
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score 1 · Answer 4 · answered Aug 09 '17 at 08:56

1

You need to declare your service in AndroidManifest.xml

<manifest ...>
   <application ...>
      <service
          android:name="package.LocationService">
      </service>
   </application>
</manifest>

answered Aug 09 '17 at 08:56

Albert Aleksieiev

107
8

kotlin android start new service

4 Answers4