Python: get CATCHA file from html

Question

I try to decode captcha on python, but I don't know, how can I get it from html. I use

html = session.get(page, headers=headers).text
soup = BeautifulSoup(html, "html.parser")

And html looks like

<img src="/captcha.gif" style="width:1px;height:1px"/>

How can I exctract it? I can do it only with save image?

Possible duplicate of [python: get image link from html](https://stackoverflow.com/questions/5927031/python-get-image-link-from-html) — Louis 'LYRO' Dupont, Aug 09 '17 at 12:48

score 0 · Answer 1 · answered Aug 09 '17 at 13:08

0

you can get image on your PC like this:

import urllib.request
from bs4 import BeautifulSoup as BS

tag = '<img src="/captcha.gif" style="width:1px;height:1px"/>'
soup = BS(tag)
img_tag = soup.find('img')
urllib.request.urlretrieve('https://absolute/path/to'+img_tag['src'], os.getcwd() + '/temp_img')

answered Aug 09 '17 at 13:08

Dmitriy Fialkovskiy

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I have an error `urllib.error.URLError: `. I check is that domain has redirect with `print(session.get(page, headers=headers).url)` and it returns me `https://moskva.tiu.ru/Tehnicheskie-moyuschie-sredstva;50` and get link to image and it looks like `/captcha.gif`, but `urllib.request.urlretrieve(page + img_link, '/Users/elenadevyataykina/PycharmProjects/parsing_contacts/captcha/')` returns error – Petr Petrov Aug 09 '17 at 14:58
I don't know how you get captcha, I made > 150 requests to page `https://moskva.tiu.ru/Tehnicheskie-moyuschie-sredstva` without pausing and didn't catch captcha page. Are you sure, you really need captcha resolving?=) – Dmitriy Fialkovskiy Aug 09 '17 at 15:24
what is the value of `page` that you pass in `rllib.request.urlretrieve()`? – Dmitriy Fialkovskiy Aug 09 '17 at 15:25
It has blocked me after ~ 3000 requests with interval 3 seconds – Petr Petrov Aug 09 '17 at 15:25
Only with url without img? – Petr Petrov Aug 09 '17 at 15:26
only `page`, img is known, isn't it? `img_link` should be equal to `"/captcha.gif"` – Dmitriy Fialkovskiy Aug 09 '17 at 15:27
`urllib.request.urlretrieve(page)` also returns an error – Petr Petrov Aug 09 '17 at 15:28
the VALUE of `page`. Like `page = https://moskva.tiu.ru` or something else – Dmitriy Fialkovskiy Aug 09 '17 at 15:28
Let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/151511/discussion-between-dmitriy-fialkovskiy-and-petr-petrov). – Dmitriy Fialkovskiy Aug 09 '17 at 15:32

Python: get CATCHA file from html

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