2

A python newbie question:

I would like to print in python with the c format with a list of parameters:

agrs = [1,2,3,"hello"]
string = "This is a test %d, %d, %d, %s"

How can I print using python as:

This is a test 1, 2, 3, hello

Thanks.

ShadowRanger
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KTran
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  • Look at https://stackoverflow.com/questions/15286401/print-multiple-arguments-in-python – perennial_ Aug 10 '17 at 19:56
  • I'd say go look here in the documentation: https://docs.python.org/3.6/library/string.html Everything is very well documented there and it should be the first place you look. – Anton vBR Aug 10 '17 at 20:02
  • @bouletta: I wouldn't call it a duplicate only because this specific question is concerned with formatting an existing `list` as sequential format items. True, you could just blindly do `string % (agrs[0], agrs[1], agrs[2], agrs[3])` and it would work, but you wouldn't necessarily understand why it worked (that you need a `tuple` specifically, and `list(agrs)` works just fine. – ShadowRanger Aug 10 '17 at 20:02

6 Answers6

6

Strings overload the modulus operator, %, for printf-style formatting, and special case tuples for formatting using multiple values, so all you need to do is convert from list to tuple:

print(string % tuple(agrs))
ShadowRanger
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5

Tuple:

Example:

print("Total score for %s is %s  " % (name, score))

In your case:

print(string % tuple(agrs))

Or use the new-style string formatting:

print("Total score for {} is {}".format(name, score))

Or pass the values as parameters and print will do it:

print("Total score for", name, "is", score)

Source

liam
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  • @ShadowRanger method work best for me because the agrs list is a variable list of parameter. the "string" is a predefine format so changing it is just making it more complicated. Thanks Liam. – KTran Aug 10 '17 at 20:43
1

Using new-style formatting: How about these one? (just experementing here) Docs: https://docs.python.org/3.6/library/string.html

args = [1,2,3,"hello"]
string = "{}, "*(len(args)-1)+"{}" # = "{}, {}, {}, {}"

'This is a test {}'.format(string.format(*args)) # inception!

Or this one:

args = [1,2,3,"hello"]
argstring = [str(i) for i in args]
'This is a test {}'.format(', '.join(argstring))

Or simply:

args = [1,2,3,"hello"]
'This is a test {}'.format(', '.join(map(str,args)))

All print:

This is a test 1, 2, 3, hello

Anton vBR
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1

The % character is not needed in following method:

agrs = [1,2,3,"hello"]
print("This is a test: {:02d},{:>10d},{:05d},{:>15s}".format(agrs[0],agrs[1],agrs[2],agrs[3]))

Same will do:

agrs = [1,2,3,"hello"]
print("This is a test: {0:02d},{1:>10d},{2:05d},{3:>15s}".format(agrs[0],agrs[1],agrs[2],agrs[3]))

Each item is formatted by what follows ":" within each curly bracket, and each of those corresponds to an argument passed on in brackets to format. For example, agrs[0] is passed and the format is "02d", which is equivalent of %02d in C.

The IT Guy
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0

Have a look at the % operator. It accepts a string and a tuple like that:

print "My age is %d and my favourite char is %c" % (16, '$')
Yotam Salmon
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l = [1,2,3,"hello"]
print("This is a test %d, %d, %d, %s"%(l[0],l[1],l[2],l[3]))

Hope this works ! Cheers bud!

Varun Shaandhesh
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