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In php, I want to pass a php variable using the jquery.post method.

The first figure shows the code that post the variable first

The second figure shows to read the posted variable.second

php variable contains some statements, but output will print the variable names like "$rxss", "$sxss".

The post method seems to be writing the data part incorrectly, so please let me know how to write it.

add

i already tested 

echo '<script type="text/javascript">
$(document).ready(function() {
$.post("scanner/getStatus.php", {testId:' . "$testId" . ',chkCnt:' . "$chkCount" . ',rxss:' . "$rxss" . ',sxss:' . "$sxss" . ',sqli:' . "$sqli" . ',basqli:' . "$basqli" . ',autoc:' . "$autoc" . ',idor:' . "$idor" . ',dirlist:' . "$dirlist" . ',bannerdis:' . "$bannerdis" . ',sslcert:' . "$sslcert" . ',unredir:' . "$unredir" . ',clamav:' . "$clamav" . '}, function(data){$("#status").html(data)});
  var refreshId = setInterval(function() {
$.post("scanner/getStatus.php", {testId:' . "$testId" . ',chkCnt:' . "$chkCount" . ',rxss:' . "$rxss" . ',sxss:' . "$sxss" . ',sqli:' . "$sqli" . ',basqli:' . "$basqli" . ',autoc:' . "$autoc" . ',idor:' . "$idor" . ',dirlist:' . "$dirlist" . ',bannerdis:' . "$bannerdis" . ',sslcert:' . "$sslcert" . ',unredir:' . "$unredir" . ',clamav:' . "$clamav" . '}, function(data){$("#status").html(data)});
}, 500); ......

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echo '<script type="text/javascript">
$(document).ready(function() {
$.post("scanner/getStatus.php", {testId:' . "$testId" . ',chkCnt:' . "$chkCount" . ',rxss:"" + $rxss + "",sxss:"" + $sxss + "",sqli:""+ $sqli + "",basqli:"" + $basqli + "",autoc:"" + $autoc + "",idor:"" + $idor + "",dirlist:"" + $dirlist + "",bannerdis:"" + $bannerdis + "",sslcert:"" + $sslcert + "",unredir:"" + $unredir + "",clamav:"" + $clamav + ""}, function(data){$("#status").html(data)});
  var refreshId = setInterval(function() {
$.post("scanner/getStatus.php", {testId:' . "$testId" . ',chkCnt:' . "$chkCount" . ',rxss:"" + $rxss + "",sxss:"" + $sxss + "",sqli:""+ $sqli + "",basqli:"" + $basqli + "",autoc:"" + $autoc + "",idor:"" + $idor + "",dirlist:"" + $dirlist + "",bannerdis:"" + $bannerdis + "",sslcert:"" + $sslcert + "",unredir:"" + $unredir + "",clamav:"" + $clamav + ""}, function(data){$("#status").html(data)});
}, 500); ......

but when these test not showing getStatus.php and apache log haven't error

k. min
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  • because you use simple quote to echo your html, so it print it literally you have do the same that you use for $testId (and you don't need to use double quote when you concatene for variable in php) – Frankich Aug 14 '17 at 09:09
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    Add your code as code to the question. **Do not** post code as screenshots/images. – ThiefMaster Aug 14 '17 at 09:11

1 Answers1

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You can you this $("$yourvariable") Also take a look at this How to call PHP function from string stored in a Variable

Minh Nguyen
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