C++ -- What is the meaning of this statement?

Question

I saw the following class definition and cannot figure out the meaning of the line 1.

class Noisy {
public:
  Noisy() throw();
 ~Noisy() throw();
  Noisy& operator= (const Noisy&) throw();
  Noisy            (const Noisy&) throw(); // Line 1
};

What is the meaning of this line and what is the usage of this line?

Thank you

score 7 · Accepted Answer · edited May 23 '17 at 12:11

7

It isn't a statement. It is a declaration of a copy constructor that is specified as throwing no exceptions.

You can find out more in your favorite good introductory C++ book.

edited May 23 '17 at 12:11

Community

1
1

answered Dec 31 '10 at 03:58

James McNellis

348,265
75
913
977

Sorry for this silly question. I should know that line if it was written as Noisy(const Noisy&) throw() -- Thank you – q0987 Dec 31 '10 at 04:13

score 0 · Answer 2 · edited May 23 '17 at 12:18

0

Look at this thread. It will give you some more insight. Should I use an exception specifier in C++?

edited May 23 '17 at 12:18

Community

1
1

answered Dec 31 '10 at 04:16

santiagoIT

9,411
6
46
57

C++ -- What is the meaning of this statement?

2 Answers2