I wrote this alternative to finding if a number was a perfect square or no how can I fix this:
n = input ('type n ')
message = ('false')
if n>0 and (math.sqrt(n)).is_integer(): message = ('true')
print (message)
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`input` returns a string. Cast to `int` – roganjosh Aug 15 '17 at 17:29
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1`math.sqrt` is floating-point arithmetic, which is approximate. – user2357112 Aug 15 '17 at 17:29