Non Integer breaking Integer input

Question

When i enter a non number in this code it breaks with this message:

Traceback (most recent call last): File "C:/Users/Default/Desktop/AS91076.py", line 12, in temp = int(input("At what Temperature do you want your wash? (Maximum 40 Degrees)")) ValueError: invalid literal for int() with base 10: 'asdf'

        temp = int(input("At what Temperature do you want your wash? (Maximum 40 Degrees)"))
        if temp < 41:
        **Misc Code**
        else:
            print("Not a valid Temperature!")

try typing `40` instead of `'asdf'` and google `if isinstance(temp, int): # do something` — Alexander McFarlane, Aug 16 '17 at 08:43
Reading between the lines - I believe what you want is covered by the linked duplicate — Jon Clements, Aug 16 '17 at 08:46
@AlexanderMcFarlane `isinstance('123', int)` returns `False` — sauerburger, Aug 16 '17 at 08:49

score 1 · Accepted Answer · answered Aug 16 '17 at 08:46

An arbitrary string can not be converted to a number. If you want to catch cases when the user types a non-integer, you can use the try statement.

try:
    temp = int(input("At what Temperature do you want your wash? (Maximum 40 Degrees)"))
    if temp < 41:
        **Misc Code**
    else:
        print("Temperature too high!")
 except ValueError as e:
        print("Not a valid Temperature!")

Non Integer breaking Integer input

1 Answers1