Javascript Regexp - Match Characters after a certain phrase

Question

I was wondering how to use a regexp to match a phrase that comes after a certain match. Like:

var phrase = "yesthisismyphrase=thisiswhatIwantmatched";
var match = /phrase=.*/;

That will match from the phrase= to the end of the string, but is it possible to get everything after the phrase= without having to modify a string?

Answer 1

You use capture groups (denoted by parenthesis).

When you execute the regex via match or exec function, the return an array consisting of the substrings captured by capture groups. You can then access what got captured via that array. E.g.:

var phrase = "yesthisismyphrase=thisiswhatIwantmatched"; 
var myRegexp = /phrase=(.*)/;
var match = myRegexp.exec(phrase);
alert(match[1]);

or

var arr = phrase.match(/phrase=(.*)/);
if (arr != null) { // Did it match?
    alert(arr[1]);
}

Answer 2

phrase.match(/phrase=(.*)/)[1]

returns

"thisiswhatIwantmatched"

The brackets specify a so-called capture group. Contents of capture groups get put into the resulting array, starting from 1 (0 is the whole match).

Answer 3

It is not so hard, Just assume your context is :

const context = "https://example.com/pa/GIx89GdmkABJEAAA+AAAA";

And we wanna have the pattern after pa/, so use this code:

const pattern = context.match(/pa\/(.*)/)[1];

The first item include pa/, but for the grouping second item is without pa/, you can use each what you want.

Answer 4

Let try this, I hope it work

var p = /\b([\w|\W]+)\1+(\=)([\w|\W]+)\1+\b/;
console.log(p.test('case1 or AA=AA ilkjoi'));
console.log(p.test('case2 or AA=AB'));
console.log(p.test('case3 or 12=14'));

Answer 5

If you want to get value after the regex excluding the test phrase, use this: /(?:phrase=)(.*)/

the result will be

0: "phrase=thisiswhatIwantmatched" //full match
1: "thisiswhatIwantmatched" //matching group