In JavaScript I can choose to be agnostic of the complete structure of some returned value during destructured assignment:
const returnsFour = () => [1, 2, 3, 4];
const [ a, b, ...c ] = returnsFour();
Now a is 1 and b is 2 and c contains whatever else was in that Array.
Can I do anything like this in Python 2.7?
A naive translation doesn't work, because the * operator only works to group stuff when in a function signature:
returnsFour = lambda: (1, 2, 3, 4)
a, b, *c = returnsFour() # syntax error
The next thing I would try is just grabbing indices of the result, but this is less pretty when you want several different indices as variables.
results = returnsFour()
a = results[0]
b = results[1]
