PHP code devided by html code doesn't work

Question

I'm not sure if this is an issue with WAMP but I have been having issues with php variables not being saved. Here is an example:

Works:

<?php 
 $x = "Hellow Wolrd!";
 echo $x;
?>

Hellow Wolrd!

Doesn't Work:

<?php 
 $x = "Hellow Wolrd!";
?>
<html>
<body> 
<?php echo $x;?>
</body>
</html>

RickyTamma What is the extension of second-code-file? `.php` or `.html`? — Alive to die - Anant, Aug 21 '17 at 09:19
If it was `.html` surely the `php` code wouldn't run in the first place? — Lewis Browne, Aug 21 '17 at 09:21
@RickyTamma both codes are in two different files? Or you just trying them in one file? — Alive to die - Anant, Aug 21 '17 at 09:22
The problem was solved. It ended up being short tag not being enabled. — RickyTamma, Aug 21 '17 at 09:28
Testing on mamP local server, it's working fine. Are you trying on a local server ? — Damien, Aug 21 '17 at 09:29
@RickyTamma but in your question you're **not** using short tag, that would be `` instead of ` — xander, Aug 21 '17 at 09:30
@xander No I wasn't, someone mentioned it, I turned it on, tested it and it worked. I call that a solution! — RickyTamma, Aug 21 '17 at 09:36
you didn't post short tag syntax here, yet you say it was so I closed the question --- *"The problem was solved. It ended up being short tag not being enabled. – RickyTamma 49 mins ago"* — Funk Forty Niner, Aug 21 '17 at 10:16

score 1 · Accepted Answer · answered Aug 21 '17 at 09:29

A blank page is either generated because the page extension is not PHP or because of a typing error in your PHP code. Try turning on error reporting on top of your PHP file by adding this as the first lines:

<?php 
error_reporting(E_ALL);
ini_set('display_errors', 1);

Perhaps you forgot a simple semicolon or bracket somewhere. Error reporting would hint you what lines you should check.

PHP code devided by html code doesn't work

1 Answers1