How to handle popup window by using python automation

Question

I am using Selenium Webdriver with Python for automation testing. While login my application I have got popup message for clicking 'OK' button. where i have used

from selenium import webdriver 
def cbs_login(): 
    browser = webdriver.Firefox() 
    browser.get('172.20.31.1:7085/web/ccp/login') 
    user = browser.find_element_by_css_selector('#userid') 
    user.send_keys('admin') 
    password = browser.find_element_by_css_selector('#password')
    password.send_keys('admin2') 
    login_location = browser.find_element_by_css_selector('#loginlocation') 
    login_location.click() 
    location_name = browser.find_element_by_xpath('/html/body/div[2]/div/div/div‌/div/div/form/div/di‌v/div/div/table/tbod‌y/tr[4]/td/select/op‌tion[3]')     
    location_name.click() 
    driver.switchTo().alert().accept(); 
    cbs_login()

i can't use the code ,I am getting error like "unresolved reference" Please mention is there any alternate way to handle it by python 2.7 version.

i searched from internet and used this driver command. am not sure about it. — Sarwan, Aug 23 '17 at 04:54
from selenium import webdriver def cbs_login(): browser = webdriver.Firefox() browser.get('http://172.20.31.1:7085/web/ccp/login') user = browser.find_element_by_css_selector('#userid') user.send_keys('admin') password = browser.find_element_by_css_selector('#password') — Sarwan, Aug 23 '17 at 05:09
password.send_keys('admin2') login_location = browser.find_element_by_css_selector('#loginlocation') login_location.click() location_name = browser.find_element_by_xpath('/html/body/div[2]/div/div/div/div/div/form/div/div/div/div/table/tbody/tr[4]/td/select/option[3]') location_name.click() driver.switchTo().alert().accept(); cbs_login() — Sarwan, Aug 23 '17 at 05:09

Andersson · Accepted Answer · 2017-08-23T05:15:10.023

2

switchTo() is not a Python method. You should try

browser.switch_to.alert.accept()

Also make sure that you have correctly import WebDriver

edited Aug 23 '17 at 05:15

answered Aug 23 '17 at 04:57

Andersson

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Krishna Satya · Answer 2 · 2017-08-23T05:20:45.123

0

Please replace driver in as told by @andersson

driver.switch_to.alert.accept()

as browser and try

browser.switch_to.alert.accept()

edited Aug 23 '17 at 05:20

answered Aug 23 '17 at 05:14

Krishna Satya

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Thanks :) now i can handle popup window. But now i am facing another problem . while login i have to select my location which will display in drop down. i am providing which drown want to select in the script , it is selecting the location but it is not displaying in location box. please help on this by checking my given code before – Sarwan Aug 23 '17 at 05:21
@Sarwan, try to implement code from [this answer](https://stackoverflow.com/questions/7867537/selenium-python-drop-down-menu-option-value/28613320#28613320) – Andersson Aug 23 '17 at 05:46
@Andresson, I tried with that scenario, in this i cont able to select the location itself. :( – Sarwan Aug 23 '17 at 10:01
from selenium import webdriver from selenium.webdriver.support.ui import Select def cbs_login(): browser = webdriver.Firefox() browser.get('url') user = browser.find_element_by_css_selector('#userid') user.send_keys('admin') password = browser.find_element_by_css_selector('#password') password.send_keys('admin2') select = browser.find_element_by_css_selector('#loginlocation') select.click() select.select_by_visible_text('WAREHOUSE') browser.switch_to.alert.accept(); cbs_login() – Sarwan Aug 23 '17 at 10:20
@Sarwan. You implemented it incorrectly. Try `select = Select(browser.find_element_by_id('loginlocation')) select.select_by_visible_text('WAREHOUSE')` – Andersson Aug 24 '17 at 07:51

How to handle popup window by using python automation

2 Answers2