How to print the characters horizontally?

Question

def rand_gen1():
    import random
    for i in range(8):
        print random.choice('0123456789abcdefghijklmnopqrstuvwxyz')

The above piece of code prints a string of 8 random chars or ints or both vertically. I need it to print like 'abcd123b' i.e. horizontally.

What changes do I need to make ?

@khelwood It would be better to concatenate though instead of printing in every iteration as SumnerEvans proposes. — Ma0, Aug 23 '17 at 14:56

score 5 · Answer 1 · answered Aug 23 '17 at 14:56

5

Or like that (+ for Richard Neumann for importing from string):

import random
from string import ascii_lowercase, digits

def rand_gen3():
    print(''.join(random.choice(ascii_lowercase + digits) for _ in range(8)))

rand_gen3()

answered Aug 23 '17 at 14:56

damisan

1,037
6
17

score 2 · Answer 2 · answered Aug 23 '17 at 14:53

You need to store the random choices in a string and then print the string:

import random

def rand_gen1():
    rand_str = ''
    for i in range(8):
        rand_str += random.choice('0123456789abcdefghijklmnopqrstuvwxyz')
    print rand_str

Each print statment creates a new line.

score 2 · Answer 3 · answered Aug 23 '17 at 14:56

2

from random import choice
from string import ascii_lowercase, digits


def rand_gen(length=8, pool=digits+ascii_lowercase):

    return ''.join(choice(pool) for _ in range(length))


print rand_gen()

answered Aug 23 '17 at 14:56

Richard Neumann

2,986
2
25
50

score 1 · Accepted Answer · answered Aug 23 '17 at 14:53

Right now you're printing out everything on its own new line by using print. You can make these all into one string by storing the values in a string variable.

import random
def rand_gen1():
    output = ""
    for i in range(8):
        output += random.choice('0123456789abcdefghijklmnopqrstuvwxyz')
    print output

How to print the characters horizontally?

4 Answers4