NSString stringWithFormat adding a percent

Question

How can I add a percent to my stringWithFormat function? For example, I'd like to have the following:

float someFloat = 40.233f;
NSString *str = [NSString stringWithFormat:@"%.02f%",someFloat];

This should cause the string to be:

40.23%

But it is not the case. How can I achieve this?

check this post: http://stackoverflow.com/questions/739682/how-to-add-percent-sign-to-nsstring — Di Wu, Jan 03 '11 at 15:55
The format specifiers can be found at http://developer.apple.com/documentation/Cocoa/Conceptual/Strings/Articles/formatSpecifiers.html — NiKKi, Jul 27 '12 at 06:29

score 86 · Accepted Answer · answered Jan 03 '11 at 15:54

86

% being the character beginning printf-style formats, it simply needs to be doubled:

float someFloat = 40.233f;
NSString *str = [NSString stringWithFormat:@"%.02f%%",someFloat];

answered Jan 03 '11 at 15:54

F'x

score 13 · Answer 2 · edited May 23 '17 at 12:25

13

The escape code for a percent sign is “%%”, so your code would look like this

[NSString stringWithFormat:@"%d%%", someDigit];

This is also true for NSLog() and printf() formats.

edited May 23 '17 at 12:25

Community

answered Jan 03 '11 at 15:56

spolu

2 Answers2