Python passing parameters as part of the function code

Question

I have 2 functions as follows:

def test1(var):
    return var*2

def test2(var):
    return var*4

I want to pass a variable to form part of the code, something like below:

var='test2'
def new_test(var,4):
    return var(4)

And I expect the output to be 16 (i.e. output from test2)

In excel, it is achievable via the function of =indirect(...). Is there any way to achieve that in Python?

@user2357112 Hello user2357112, it is because my current problem has to do with creating a function that takes an argument which will form part of the script within the function. I just revised my codes above for further clarity. — user7786493, Aug 27 '17 at 05:23
In the above case, I have a new function that takes an argument (var) which will either be test1 or test2. And inside the function of new_test, it is written in a way that the argument (var) will either be test1 or test2. — user7786493, Aug 27 '17 at 05:25
I'm still not seeing anything here that requires you to use a string instead of the actual function object. — user2357112, Aug 27 '17 at 05:25
user2357112, do you mean that in this case I can simply type test1 (as an object without single quotation) as an argument passing into the new_test as follows: print(new_test(test2,4)) — user7786493, Aug 27 '17 at 05:28

score 1 · Answer 1 · answered Aug 27 '17 at 05:28

1

Yes, instead of this:

var = 'test2'

def new_test(var, 4):
    return var(4)

You can do this directly:

var = test2

def new_test(var, 4):
    return var(4)

Functions are first class objects in Python.

answered Aug 27 '17 at 05:28

wim

1 Answers1