How to filter an array in javascript?

Question

This is an array:

total = ["10%", 1000, "5%", 2000]

How can I filter these into two arrays like:

percentage = ["10%","5%"]
absolute = [1000,2000]

...using JavaScript array filter.

Answer 1

You should use filter method, which accepts a callback function.

The filter() method creates a new array with all elements that pass the test implemented by the provided function.

Also, use typeof operator in order to find out the type of item from array. The typeof operator returns a string indicating the type of the unevaluated operand.

let total = ["10%", "1000", "5%", "2000"];
let percentage = total.filter(function(item){
  return typeof item == 'string' && item.includes('%');
});
console.log(percentage);
let absolute = total.filter(function(item){
  return typeof item == 'number' || !isNaN(item);
});
console.log(absolute);

Answer 2

let total = ["10%", 1000, "5%", 2000];

let percents = total.filter(item => item.toString().includes('%'));
let numbers = total.filter(item => !item.toString().includes('%'));
console.log(percents, numbers);

Answer 3

Make two arrays from one array by separating number and string using advance  
js.

let total = ["10%", 1000, "5%", 2000];
var percentage = total.filter(e => isNaN(e));
var absolute = total.filter(e => !isNaN(e));
console.log({percentage , absolute});

Answer 4

You can use regular expressions since you have only strings in your array.

For % :

total.filter(function(element){
    return /^[0-9]+\%$/gi.test(element);
});

For absolute :

total.filter(function(element){
    return /^[0-9]+$/gi.test(element);
});

Answer 5

You can use Array#reduce to split the array:

const total = ["10%", 1000, "5%", 2000];

const { absolute, percentage } = total.reduce((arrs, item) => {
  const key = typeof item === 'number' ? 'absolute' : 'percentage';
  
  arrs[key].push(item);
  
  return arrs;
}, { percentage: [], absolute: [] });

console.log(absolute);

console.log(percentage);

Answer 6

For brevity with using ES2015 , if you plan to simply clear the array (this is an example, insert your own function for element "e", of course):

let MyArray = [1,2,3,4,5]

MyArray = [].concat(MyArray.filter(e => e > 2))

console.log(MyArray)

Answer 7

you can do it using

let total = ["10%", 1000, "5%", 2000]


let result1 = total.filter(function(element){
    if(typeof element == "number"){
        return 1;
    }
    return 0;
})
let result2 = total.filter(function(element){
    if(typeof element == "string" && element.match(/\%$/)){
        return 1;
    }
    return 0;
})
console.log(result1, result2);

the first array filter all the number
the 2nd array filter elements which are a string and have a "%" in the end

Answer 8

use this code

$array = array('10%', '1000', '20%','2000');

//for show integer from array

print_r(array_filter($array, function ($var) { return (stripos($var, '%') === false); }));

//for show % array

print_r(array_filter($array, function ($var) { return (stripos($var, '%') == true); }));

Answer 9

let total = ["10%", "1000", "5%", "2000"];
let percentage = total.filter(function(item){
  return typeof item == 'string' && item.includes('%');
});
console.log(percentage);
let absolute = total.filter(function(item){
  return typeof item == 'number' || !isNaN(item);
});
console.log(absolute);