initiate bitset with an integer declared in my function in c++

Asked Aug 28 '17 at 13:45

Active Aug 28 '17 at 13:45

Viewed 28 times

I want to do

    int count=32;
    bitset<count>(a);

I have not put my entire code as it was irrelevant the basic thing is that I have to create a bitset of a given length and that length is calculated in the program. But this throws an error showing count cannot appear in a constant expression. What would be the solution to this.

asked Aug 28 '17 at 13:45

Ram Sharma

The N in `std::bitset` must be constant. If you need variable-sized bitsets you should look elsewhere. – Banex Aug 28 '17 at 13:48
Template parameters have to be available at compile time. – Barmar Aug 28 '17 at 13:48
The template parameter should be a compile time constant for `std::bitset` – P0W Aug 28 '17 at 13:48
@barmar is there any way to do this using bitset if not what alternative would you suggest – Ram Sharma Aug 28 '17 at 13:49
1

Use a vector of bits instead of a bitset? – Barmar Aug 28 '17 at 13:50
You can use [_`dynamic_bitset`_](http://www.boost.org/doc/libs/1_65_0/libs/dynamic_bitset/dynamic_bitset.html) – P0W Aug 28 '17 at 13:53

initiate bitset with an integer declared in my function in c++

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