C++ deconstructor message not shown

Asked Aug 28 '17 at 17:49

Active Aug 28 '17 at 18:06

Viewed 42 times

When executing the following code the constructor messages for both objects appear, but the destructor messages appear only for the 'hattie' object. Weren't destructors for both objects run on exit? Note that the base class destructor is protected, satisfying Sutter's rule #4.

#include <iostream>
#include <string>
using namespace std;

class Pup {
protected:
    string name ;
    ~Pup() {cout << "bye " + name << endl;}
};

class Corgi : public Pup {
public:
    Corgi(string name) {this->name = name ;
        cout << "hello " + name << endl;}
    ~Corgi() {cout << "bye-bye " + name << endl;}
};

int main() {
    Corgi hattie("Hattie");
    Corgi* gus = new Corgi("Gus");
    return 0;
}

edited Aug 28 '17 at 18:06

asked Aug 28 '17 at 17:49

user3150422

2

You used `new` without `delete`. – Ry- Aug 28 '17 at 17:50
1

You never call `delete gus;` so what do you expect? – user0042 Aug 28 '17 at 17:50
1

when you use `new` you **must** use `delete` sometime afterwards. – NathanOliver Aug 28 '17 at 17:51
Not strictly true, guys; if you change the stmt creating hattie as shown below, the destructor for hattie is run on exit without calling delete. Corgi hattie = *(new Corgi("Hattie")); – user3150422 Aug 28 '17 at 18:17
C++ ain't Java innit. You need to call the destructor yourself. Use delete explicitly or, better still, a smart pointer type. Also the Pup destructor ought to be marked virtual. – Bathsheba Aug 28 '17 at 18:19
1

@user3150422: That’s the destructor for another `Corgi`; you copied it. – Ry- Aug 28 '17 at 18:28
OT: ~Pup() should be virtual. – Aug 28 '17 at 18:35

C++ deconstructor message not shown

0 Answers0