I know that
Object.getPrototypeOf(Object.getPrototypeOf(Object)) === Object.prototype; // true
But why they design Object like this?
function A(){};
A.prototype = A.__proto__ = new A();
A instanceof A;// true
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magmaliang
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1What's the issue? – evolutionxbox Aug 29 '17 at 09:59
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https://stackoverflow.com/questions/9959727/proto-vs-prototype-in-javascript – evolutionxbox Aug 29 '17 at 10:10
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Notice that in your example, `Object.getPrototypeOf(Object.getPrototypeOf(A)) == A.prototype` does *not* hold – Bergi Aug 29 '17 at 10:42
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@Bergi you are right, the example just show the first layer,Object's proto chain is deeper.... – magmaliang Oct 09 '17 at 12:01
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How else would they have designed it? It follows naturally from the rules "The Object constructor is a function", "Every function inherits from Function.prototype", "Every function is an object" and "Every object inherits from Object.prototype".
Bergi
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