Converting a split string representation of a list into a string

Question

i have read up on remove the character 'u' in a list but it does not work in my case :

[u"[u'DUTY,", u'RHODE', u'ISLAND', u'STATE', u'ASSOCIATION', u'OF', u'FIRE', u"OF']"]

**Expected Output** : DUTY RHODE ISLAND STATE ASSOCIATION OF FIRE OF

If i use :

list = [u"[u'DUTY,", u'RHODE', u'ISLAND', u'STATE', u'ASSOCIATION', u'OF', u'FIRE', u"OF']"]

new_list = "%s, %s" % (list[-1], ' '.join(list[:-1]))

Output will : u"OF'], [u'DUTY, RHODE ISLAND STATE ASSOCIATION OF FIRE FIGHTERS LINE"

If

next_list = [str(' '.join(filter(None, new_list)))]
Output is: ["[u'DUTY, RHODE ISLAND STATE ASSOCIATION OF FIRE FIGHTERS LINE OF']"]

If :

import ast
ast.literal_eval(' '.join(list))[0]

Output is : u'DUTY, RHODE ISLAND STATE ASSOCIATION OF FIRE FIGHTERS LINE OF'

Thanks

i guess this answer your question. https://stackoverflow.com/questions/1207457/convert-a-unicode-string-to-a-string-in-python-containing-extra-symbols — Kamilo Vasquez Caro, Sep 01 '17 at 05:59

cs95 · Accepted Answer · 2017-09-01T05:56:05.557

1

You should be able to do this quickly using ast.literal_eval:

import ast

s = ["[u'DUTY,", 'RHODE', 'ISLAND', 'STATE', 'ASSOCIATION', 'OF', 'FIRE', "OF']"]
out = ast.literal_eval(' '.join(s))[0]

print(str(out)) # the str bit is redundant for python3
'DUTY, RHODE ISLAND STATE ASSOCIATION OF FIRE OF'

edited Sep 01 '17 at 05:56

answered Sep 01 '17 at 05:49

cs95

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using your methods output is: u'DUTY, RHODE ISLAND STATE ASSOCIATION OF FIRE FIGHTERS LINE OF' – helpdoc Sep 01 '17 at 05:55
there are extra u in list – helpdoc Sep 01 '17 at 05:55
@SNTiwari Run `out = str(out); print(out)` – cs95 Sep 01 '17 at 05:55

Converting a split string representation of a list into a string

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