Counting the occurrence of unique letters in a string in Python 3

Question

There are many way for Counting the occurrence of unique letters in a string in Python 3. I just wanna know what is the best way for this job. Thanks.

Welcome to Stack Overflow. If you are aware of the many ways to count the occurrences of unique letters, you should be able to write a benchmark that compares them in order to determine which is best. This is not a homework completion service. — Ken White, Sep 05 '17 at 04:38
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score 1 · Accepted Answer · edited Dec 04 '18 at 16:36

1

if you need to count characters in string, try the following

a = "aaabbcccd"
b = dict.fromkeys(a, 0)
for i in a:
    b[i] += 1

b now holds the counts you require:

{'a': 3, 'c': 3, 'b': 2, 'd': 1}

edited Dec 04 '18 at 16:36

Heemanshu Bhalla

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answered Sep 05 '17 at 10:46

BA.

924
7
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score -1 · Answer 2 · answered Sep 05 '17 at 04:58

-1

try:

''.join(set('aaabbbcccdddd'))

or:

list(set('aaabbbcccdddd'))

Also see the post: List of all unique characters in a string?

answered Sep 05 '17 at 04:58

BA.

924
7
10

i didn't meant that. imeant: aabbcda a 3 b 2 c 1 d 1 – Sep 05 '17 at 05:06

Counting the occurrence of unique letters in a string in Python 3

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