Python conditional evaluation

Question

I expect below code to work properly, since first condition if false, but it throughs IndexError: string index out of range. What am I missing?

 a = False
 sample_strign = 'test'
 if (a == True) & (sample_strign[7] == 's'):
        print('foo')

Also, it's more Pythonic to check just `a` or even `a is True` than `a == True` — Mad Physicist, Sep 05 '17 at 20:01
Possible duplicate of [Boolean operators vs Bitwise operators](https://stackoverflow.com/questions/3845018/boolean-operators-vs-bitwise-operators) — Mad Physicist, Sep 05 '17 at 20:03

score 6 · Accepted Answer · answered Sep 05 '17 at 19:57

6

& is a bit-wise operator. If you want the interpreter to "short-circuit" the logic, use the logical operator and.

if a and (sample_strign[7] == 's'):

answered Sep 05 '17 at 19:57

Billy

score 1 · Answer 2 · answered Sep 05 '17 at 20:00

1

sameple_strign doesn't have a 7th index which will raise an exception, you should use something like:

if a and len(sample_strign) > 7:
    if sample_strign[7] == 's':
        print('foo')

answered Sep 05 '17 at 20:00

Mohd

2 Answers2