Initialising inherited structure with initialiser list

Asked Sep 07 '17 at 12:56

Active Sep 07 '17 at 12:59

Viewed 42 times

I'm trying the following:

struct A
{
    int x;
};

struct B: A
{
    int y;
};

B foo = {1, 2};

But I get:

error: could not convert '{1, 2}' from '<brace-enclosed initializer list>' to 'B'

This is using C++11. Can I get round it without defining an explicit constructor?

edited Sep 07 '17 at 12:59

asked Sep 07 '17 at 12:56

Stefan

You don't need the public, by the way. Access is public by default for structs. – flau Sep 07 '17 at 12:58
1

no. Having said that I seem to remember seeing a proposal somewhere that would allow it in a future version of c++. – Richard Hodges Sep 07 '17 at 12:58
@Richard Hodges the duplicate marked has a link to the proposal just fyi. – Samer Tufail Sep 07 '17 at 13:04
@SamerTufail many thanks, although I wouldn't use it even if I could - so brittle!. – Richard Hodges Sep 07 '17 at 13:06
@Richard Hodges agreed. I would prefer an explicit ctor. – Samer Tufail Sep 07 '17 at 13:10

0 Answers0