How to leave 2 digits in printf using %d

Question

main ()
{
    int a; // Dabartine data
    int b; // Gimimo data
    int c;
    printf("Iveskite dabartine data formatu yymmdd:");
    scanf("%d", &a);
    printf("Iveskite savo gimimo data formatu yymmdd:");
    scanf("%d", &b);
    c = a - b;
    printf("Jusu amzius yra %d metai", c);
    return 0;
}

Could someone tell me how to make that in the end the result would be only 2 digits? It is a code to calculate your age accordingly to current date and date of birth. The answer is in yymmdd format and I need to remove the mmdd part and leave only the year part, for example: it prints 180602, and I only need to leave 18(it is the age of person)

This question is not actually about printing `4` as `04` or anything. I think it's asking how to turn `920915` into `92`. — melpomene, Sep 09 '17 at 14:51
@melpomene - if that is the case, divide the value by `10000` and print that. The indicated duplicate is relevant then. — Peter, Sep 09 '17 at 14:54
You could add example to the question to show it's not a duplicate. — hyde, Sep 09 '17 at 15:04

score 2 · Accepted Answer · answered Sep 09 '17 at 14:52

2

You could try c = (a - b)/10000; That will discard the last 4 digits without rounding up.

answered Sep 09 '17 at 14:52

Chang Qian

1,091
8
15

Thanks, damn I'm stupid couldn't think of this simple solution :// – mjay99 Sep 09 '17 at 14:58

How to leave 2 digits in printf using %d

1 Answers1