Python create file safely

Question

I want create file safely in python2.7

import os
import sys
logname = "logfile"
f = open(logname, 'w')
sys.stdout = f
print "file created with file name {}".format(logname)
f.close()

Above script will overwrite if file is exist. I dont want to recreate it.

Say if file name "logfile" already exist, try to create with "logfile1" name.

Can't you just check if the file exists before trying to create it? — Carcigenicate, Sep 10 '17 at 14:32
Possible duplicate of [Safely create a file if and only if it does not exist with python](https://stackoverflow.com/questions/10978869/safely-create-a-file-if-and-only-if-it-does-not-exist-with-python) — Peter Wood, Sep 10 '17 at 14:38
You could open in `a` mode for appending to an existing file or create if not exists. — OneCricketeer, Sep 10 '17 at 14:42

score 0 · Answer 1 · answered Sep 10 '17 at 14:33

You can use os.path.isfile to check if the file already exists

if os.path.isfile(logname):
    logname = increment(logname) # increment the filename
f = open(logname, 'w')
sys.stdout = f
print "file created with file name {}".format(logname)
f.close()

Depending on your naming conventions, there are multiple ways you could implement your increment function

Python create file safely

1 Answers1