How to make default time zone apply in Spring Boot Jackson Date serialization

Question

I have configured my Spring Boot application to serialize dates as ISO8601 strings:

spring:
  jackson:
    serialization:
      write-dates-as-timestamps: false

This is what I am getting:

"someDate": "2017-09-11T07:53:27.000+0000"

However my time zone is Europe/Madrid. In fact if I print TimeZone.getDefault() that's what I get.

How can I make Jackson serialize those datetime values using the actual timezone? GMT+2

"someDate": "2017-09-11T09:53:27.000+0200"

score 37 · Accepted Answer · answered Sep 11 '17 at 09:05

37

Solved registering a Jackson2ObjectMapperBuilderCustomizer bean:

@Bean
public Jackson2ObjectMapperBuilderCustomizer jacksonObjectMapperCustomization() {
    return jacksonObjectMapperBuilder -> 
        jacksonObjectMapperBuilder.timeZone(TimeZone.getDefault());
}

answered Sep 11 '17 at 09:05

codependent

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Hello, after adding this config and use @JsonFormat annotation with specific pattern it does not seem to find the default timezone: `@JsonFormat(pattern = "yyyy-MM-dd")` – skywalker Dec 12 '22 at 12:24

Jaumzera · Answer 2 · 2019-02-26T19:35:54.453

35

I found myself with the same problem. In my case, I have only one timezone for my app, then adding:

spring.jackson.time-zone: America/Sao_Paulo

in my application.properties solved the problem.

Source: https://docs.spring.io/spring-boot/docs/current/reference/html/common-application-properties.html#JACKSON

edited Feb 26 '19 at 19:35

answered Dec 21 '17 at 18:42

Jaumzera

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score 32 · Answer 3 · answered Sep 11 '17 at 12:08

32

You can set timezone for whole application with adding this to a config class:

@PostConstruct
void started() {
    TimeZone.setDefault(TimeZone.getTimeZone("UTC"));
}

answered Sep 11 '17 at 12:08

barbakini

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2

Jackson won't pick that up. The default TimeZone is the right one. My solution solves it. Thanks anyway – codependent Sep 11 '17 at 12:56
4

@codependent I use jackson in my project too and this configuration solved my problem for time zones. Anyway if you solve your problem, nothing to argue :) I will just leave my post if anybody can use it. Happy coding. – barbakini Sep 11 '17 at 16:06
yes this will work, it depends where in your application you are setting default time zone. this work's good because now ur application will not do any time adjustment. – Arun Pratap Singh Jun 01 '18 at 07:23
This sets the "target" timezone of (de)serialization, while the `JsonFormat(timezone = "xxx")` sets the input timezone of (de)serialization when parsing as well as formating. See [another question of mine](https://stackoverflow.com/questions/53322376/simpledateformat-with-timezone-set-gets-correct-value-but-wrong-zone?noredirect=1#answer-53337257) for details. – WesternGun Nov 19 '18 at 08:47
@barbakini solution solved my problem. In my case I save OffsetDateTimes on database as offset "+00:00" (or "Z"), and when retrieving them, the applicaiton automatically added the offset. With this setting it doesn't. Thanks! :) – Fer B. Nov 11 '22 at 19:44

score 6 · Answer 4 · answered Dec 05 '19 at 20:00

There are 2 solutions for this:

1. Add JSON format annotation

@JsonFormat(shape = JsonFormat.Shape.STRING, timezone = "Asia/Kolkata")
private Date insertionTime;

2. Add Jackson time zone to properties (spring boot)

spring.jackson.time-zone: America/Sao_Paulo

Reference : https://www.baeldung.com/spring-boot-formatting-json-dates

How to make default time zone apply in Spring Boot Jackson Date serialization

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