Comparing functions in swift

Asked Sep 11 '17 at 11:29

Active Sep 11 '17 at 11:29

Viewed 107 times

I just discovered that there is no possible straightforeward way to compare two functions in swift, meaning this code does not compile:

func foo1() {}
func foo2() {}
assert(foo1 === foo1)
assert(foo1 !== foo2)

This strikes me, because I know functions use reference semantics and therefore it shouldn't be a problem to compare two references, as it is possible in C with function pointers.

Can anyone provide me an explanation of this restriction and does anyone know a workaround for this?

asked Sep 11 '17 at 11:29

tierriminator

Out of curiosity, what are the errors? – Carcigenicate Sep 11 '17 at 11:33
cannot check reference equality of functions; operands here have types '() -> ()' and '() -> ()' – tierriminator Sep 11 '17 at 11:35
2

Swift is not supporting function or closure equality as of now. Please check this thread : https://stackoverflow.com/questions/24111984/how-do-you-test-functions-and-closures-for-equality – technerd Sep 11 '17 at 11:41
Oh, great, thanks, I somehow didn't find those answers – tierriminator Sep 11 '17 at 11:42

Comparing functions in swift

0 Answers0