UNIX Replace string without replacing space

Asked Sep 11 '17 at 14:22

Active Sep 11 '17 at 14:22

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I have a problem with UNIX script.

original_string='AGENT                               UNKNOWN'
replacement=`echo $original_string | sed 's/UNKNOWN/ACTIVE/g'`
echo $replacement

The result of this script gives me :

AGENT ACTIVE

But I want to maintain all the spaces between the characters like:

AGENT                               ACTIVE

Someone please help.

asked Sep 11 '17 at 14:22

Bhabani Shankar

1

Quote your variable: `replacement=$(echo "$original_string" | sed 's/UNKNOWN/ACTIVE/g')` – anubhava Sep 11 '17 at 14:26
The idea is as @anubhava mentioned to use double-quotes around shell variable containing the spaces – Inian Sep 11 '17 at 14:34
Use quote echo "$replacement" (see https://stackoverflow.com/questions/37306796/keep-spaces-when-using-sed-command-in-kornshell-script) – montardon Sep 11 '17 at 14:35
It works ... Thanks a lot – Bhabani Shankar Sep 11 '17 at 15:38

0 Answers0