When displaying the address of an individual member of a struct/class, the displayed address is the one of the whole structure.
Indeed,
#include <iostream>
struct S {
int x;
int y;
};
int main() {
S s;
std::cout<<&s<< " --- "<<&(s.x)<<std::endl;
}
will print e.g. 0x7ffd4e882780 --- 0x7ffd4e882780.
I found many posts that relate about manipulating individual members of a struct by using recipes such as
int S::*p = &S::x;
S* ptr = &s;
ps->*ptr = 1000;
which may be related in some way to my question but I could not find one that explains why the individual address of x within the struct layout is the same (at least displayed) as the one of of the struct. I guess that I miss something obvious but do not find what. Would you have any idea ?
