What is java.lang.ArrayIndexOutOfBoundsException?

Question

Hi I'm beginner to java program, I'm getting one exception error in common sort array program

      public static void main(String[] args) {
    // TODO Auto-generated method stub
    int[] arr1={4,5,6,8};
    int[] arr2={5,4,2,1};
    int[] arr3={4,5,3,2};

    for(int i=0;i<=arr1.length;i++){
        for(int j=0;j<=arr2.length;j++){
           for(int k=0;k<=arr2.length;k++){

             if(arr1[i]==arr2[j] && arr2[j]==arr3[k])
             {
                System.out.println(arr3[k]);
             }

          }
       }
    }

}

Remove all `<=` and write only `<`. Arrays are indexed from 0 to length -1 only. — Deepansh Sachdeva, Sep 16 '17 at 06:57
Thanks, @DeepanshSachdeva can you please explain me the full code. — samkarthick, Sep 16 '17 at 07:27
That should be your job to understand. Also, I would like to tell that this code doesn't seem to sort anything, it just prints common values from all array. — Deepansh Sachdeva, Sep 16 '17 at 07:37

score 0 · Answer 1 · answered Sep 16 '17 at 07:39

0

Java has array indexed from 0 to length - 1. So instead of less than equal to operator <= you should use less than operator < in this case.

answered Sep 16 '17 at 07:39

Deepansh Sachdeva

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score 0 · Answer 2 · answered Sep 16 '17 at 08:50

The problem is in for loop condition, you have only 4 elements in array and array index start with zero so your loop must start from 0 to 3 but <= operator checks for the forth index in array which not exist so just use < so the loop terminates after evaluating last index

What is java.lang.ArrayIndexOutOfBoundsException?

2 Answers2