Android regarding number format exception

Question

[65,98]09-19 15:26:29.452 19498-19498/co.helpdesk.faveo.pro W/System.err: java.lang.NumberFormatException: For input string: "65,98"
09-19 15:26:29.453 19498-19498/co.helpdesk.faveo.pro W/System.err:     at java.lang.Integer.parseInt(Integer.java:521)
09-19 15:26:29.453 19498-19498/co.helpdesk.faveo.pro W/System.err:     at java.lang.Integer.parseInt(Integer.java:556)

can anyone tell me how to convert this into an integer? I am getting this as 65,98 but it is telling me number format exception,

Please tell me how to solve this problem.

You cannot parse string contain with `comma (,)` in it with Integer — akhilesh0707, Sep 19 '17 at 10:07
Then what will be the solution? i am getting this [65,98,66,78].....then how to convert this into integer? — sayar samanta, Sep 19 '17 at 10:11
It's comma separated array containing intValue you need to split from `'` — akhilesh0707, Sep 19 '17 at 10:12
Sorry @akhilesh0707 i am not getting if you can explain me then it will be good. — sayar samanta, Sep 19 '17 at 10:14

score 1 · Answer 1 · answered Sep 19 '17 at 11:09

Parse the string into int. You can use split method as from documentation to parse each value separated by comma.

if(!yourData.isEmpty()){
    String[] result = yourData.split(",");
    int varOne = Integer.parseInt(result[0]);
    int varTwo = Integer.parseInt(result[1]);
}

Android regarding number format exception

1 Answers1