arithmetic progression in python 3.6 in def function

Question

I write python code in atom editor and make program arithmetic sequence in function

this is the code:

def arithmetic(n):
flag = n

for flag in range(10):
    number = []
    result =  number.append(flag**2)
    return result

the result when print(arithmetic(5)):

None

Possible duplicate of [Why does append return none in this code?](https://stackoverflow.com/questions/16641119/why-does-append-return-none-in-this-code) — Chris_Rands, Sep 20 '17 at 13:54

skr · Accepted Answer · 2017-09-20T14:22:59.160

1

Check this code.

def arithmetic(n):
    flag = n
    number = []
    for flag in range(10):
        number.append(flag**2)
    return number

print (arithmetic(4))

edited Sep 20 '17 at 14:22

answered Sep 20 '17 at 14:18

skr

In Python 3.x this will raise an error. You need parenthesis when calling `print` – Eskapp Sep 20 '17 at 14:21
1

Thank you @Eskapp I just tested only in 2.7 version – skr Sep 20 '17 at 14:23
You're so helpful @skr – Muhammad Akbar Sep 20 '17 at 14:29
Glad I could help @MuhammadAkbar – skr Sep 20 '17 at 14:40

1 Answers1