Removing "Optional" in Swift 4

Question

That's my code

let temperature = String(describing: Int(incomeTemp.text!))

celcjuszScore.text = "\(temperature)"
print(temperature)

Whent I am pushing a button, the result of print is "Optional(32)" (When I am writing 32 in incomeTemp). I would like to have "Optional" removed and only "32" should stay.

Why not just use the text as is, instead of converting it into an int and then immediately back into a string? — John Montgomery, Sep 20 '17 at 16:19
Side note: don't use `String(describing: xyz)` to make a string from an int, just use `String(xyz)`. The "describing" is actually the same as `xyz.description` which does not always represent the string content as you would expect. — Eric Aya, Sep 20 '17 at 16:56

score 3 · Accepted Answer · answered Sep 20 '17 at 16:02

3

Just unwrap it.

if let temperature = Int(incomeTemp.text!) {
    celcjuszScore.text = "\(temperature)"
    print(temperature)
}

answered Sep 20 '17 at 16:02

sCha

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score 1 · Answer 2 · answered Sep 20 '17 at 16:03

Remove the optional when converting text to number: Int(incomeTemp.text!) ?? 0.

Or solve the error explicitly:

if let temperature = Int(incomeTemp.text ?? "") {
   celcjuszScore.text = "\(temperature)"
} else {
   celcjuszScore.text = "Invalid temperature"
}

Removing "Optional" in Swift 4

2 Answers2