<?php
require("../config/config.php");
require("../lib/db.php");
$_POST['id'] = $uid;
$_POST['pw'] = $upwunenc;
$conn = db_init($config["host"],$config["duser"],$config["dpw"],$config["dname"]);
$result = mysqli_query($conn, "SELECT * FROM userdata");
$sql = "SELECT id,pw,nickname,pid FROM userdata WHERE id LIKE '$uid'";
$result = mysqli_query($conn, $sql);
$row = mysqli_fetch_assoc($result);
$row['id'] = $sqlid;
$row['pw'] = $sqlpw;
$row['nickname'] = $sqlni;
$row['pid'] = $sqlpid;
$upw = password_hash($upwunenc, PASSWORD_DEFAULT);
if ($uid === $sqlid) {
if ($upw === $sqlpw) {
$resulti = mysqli_query($conn, 'SELECT * FROM sitestatements');
$sqli = 'SELECT link,pid FROM sitestatements WHERE upid = '.$_GET['pid'];
$resulti = mysqli_query($conn, $sqli);
$rowi = mysqli_fetch_assoc($resulti);
$rowi['link'] = $link;
session_start();
$_SESSION['pid'] = $sqlpid;
$_SESSION['nickname'] = $sqlni;
header('Location: ./index.php');
} else {
echo "<script>window.alert('아이디나 비밀번호가 틀렸습니다. 회원가입하거나 다시 로그인해주세요.');</script>";
echo "<script>window.location=('../login/login.php');</script>";
}
} else {
echo "<script>window.alert('아이디나 비밀번호가 틀렸습니다. 회원가입하거나 다시 로그인해주세요.');</script>";
echo "<script>window.location=('../login/login.php');</script>";
}
?>
Notice: Undefined Variable: uid upwunenc uid sqlid sqlpw sqlpid upwunenc splid uid sqlpw
I Can't Find the Reason Why It's Happening. How Can I Fix It?
