object of type 'NoneType' has no len() :

Question

def send_ivr_calls(sp_orders, base_url, api_key, extra_data):
    for contact in sp_orders:
        if len(contact) == 10:
            contact = '0'+contact

File "views.py", line 43, in calls if len(contact) == 10:
TypeError: object of type 'NoneType' has no len()

How can I check whether the sp_orders list does not contain any Nones?

Kyle Higginson · Accepted Answer · 2017-09-21T10:53:22.293

3

Try this:

def send_ivr_calls(sp_orders, base_url, api_key, extra_data):
    for contact in sp_orders:
        if contact and len(contact) == 10:
                contact = '0'+contact

This is ensures contact is not None before you try to get its length. Credit to @Moses Koledoye for pointing out short-circuiting.

edited Sep 21 '17 at 10:53

answered Sep 21 '17 at 10:19

Kyle Higginson

922
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2

Why not use one *if* clause and shortcircuit with `and`. Although the parser is very likely to fix it so it might not be much of a problem. – Moses Koledoye Sep 21 '17 at 10:20
3

`if contact and len(contact) == 10` won't break. If contact is *falsy*, it's length will never be checked. – Moses Koledoye Sep 21 '17 at 10:26
@Kyle Higginson, [good thread about short-circuiting](https://stackoverflow.com/questions/2580136/does-python-support-short-circuiting) – CommonSense Sep 21 '17 at 10:30

score 1 · Answer 2 · answered Sep 21 '17 at 10:20

1

if contact is not None and len(contact) == 10:
    contact = '0'+contact

answered Sep 21 '17 at 10:20

Dmitry

6,716
14
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object of type 'NoneType' has no len() :

2 Answers2