Python not returning a decimal when expected

Asked Sep 24 '17 at 06:16

Active Sep 24 '17 at 07:09

Viewed 33 times

scores = [20, 20, 20, 10, 9, 8]
if scores[0] == max(scores):
    win = (1/(scores.count(max(scores))))
    print win

I would expect this to return: 0.333

Instead it returns: 0

I put in some debugging code and confirmed that:

The if condition is being met. The subsequent code is being executed.
(scores.count(max(scores))) is returning a value of 3

So it would seem that win should obviously be set to 1/3, but it's being set to 0. I tried initializing the win variable as a float, but it made no difference.

edited Sep 24 '17 at 07:09

Kaushik NP

6,733
9
31
60

asked Sep 24 '17 at 06:16

Justin

Hmmm. It works in `Python3` properly, but in `Python2`, this happens. – Kaushik NP Sep 24 '17 at 06:20
1

Initializing a variable with a value of one type doesn't affect the type of anything you assign to it later. – user2357112 Sep 24 '17 at 06:20

Python not returning a decimal when expected

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