Swift string after specific index

Question

I want to know how to get rest of string after specific character.

I have checked link

but have not found answer.

Consider following code:

let fullString = "Blue Sky"
let spaceIndex = fullName.index(of: " ")!

I know i can get first string before like that:

let firstString = fullString[fullString.startIndex..<spaceIndex] // "Blue”

But let firstString = fullString[fullString.startIndex..>spaceIndex] // "Blue” not work.

What i want is - "Sky". How to get it?

@ShamasS space is just example. I need to know how to separate after specific character. — Evgeniy Kleban, Sep 26 '17 at 08:13
:) You already know how to find the position of a specific character, go through the answer that I posted, it tells you how to get a range. — Shamas S, Sep 26 '17 at 08:14
@ShamasS in my question i wrote that i didnt found solution in answer you linked. — Evgeniy Kleban, Sep 26 '17 at 08:15
Y'all should keep arguing about what's not there rather than actually just posting the answer @Sharmas S. That's a much better use of the time. — ChrisH, May 25 '23 at 19:50

RajeshKumar R · Accepted Answer · 2019-05-17T06:02:29.110

7

You can separate the sentence into array of words and get last word. Try this. You can replace " " with any character or string.

let fullString = "Blue Sky"
print(fullString.components(separatedBy: " ").last)//Sky

Or

if let index = fullString.firstIndex(of: " ") {
    print(fullString[index...])//Sky
}

edited May 17 '19 at 06:02

answered Sep 26 '17 at 08:17

RajeshKumar R

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score 3 · Answer 2 · answered Sep 26 '17 at 08:19

components(separatedBy:) will split your string into an array of strings enabling you to access the different elements in the array using indexes.

 let fullString = "Blue Sky"    
 let splitString = fullString.components(separatedBy: " ")

 print("Part before space: \(splitString[0])") // Part before space: Blue
 print("Part after space: \(splitString[1])") // Part after space: Sky

score 2 · Answer 3 · answered Sep 26 '17 at 08:19

2

There is no such operator as ..> in Swift.

However, you can use the ..< operator, as in fullString[spaceIndex..<fullString.endIndex].

Or, in Swift 4, you can just: fullString[spaceIndex...].

answered Sep 26 '17 at 08:19

Charles Srstka

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unfortunatelly it contain "space" character as well. I dont need it. – Evgeniy Kleban Sep 26 '17 at 08:23
Then you can: `fullString[fullString.index(after: spaceIndex)...]` – Charles Srstka Sep 26 '17 at 08:24

Swift string after specific index

3 Answers3