How to make a "reference" to an array by string in php

Question

I have a problem which I'm unable to solve (in an easy way) at the moment:

$clients = array("A", "B");

$array_data_A = array(
    array("1000733", "1.6.0"),
    array("1000733", "1.8.0"),
    array("1000733", "1.8.1"),
    array("1000733", "1.8.2"),
    array("1000733", "1.8.3"),
    array("1000733", "1.8.4"),
);

$array_data_B = array(
    array("1000733", "1.6.0"),
    array("1000733", "1.8.0"),
    array("1000733", "1.8.1"),
    array("1000733", "1.8.2"),
    array("1000733", "1.8.3"),
    array("1000733", "1.8.4"),
);

Now I can make this:

foreach ($clients as $client) {

    // won't work
    $data_array = '$array_data'.$client;
    getsqldata($client, $data_array);

    // works
    switch ($client) {
        case "A":
            getsqldata($client, $array_data_A);
            break;
    }
}

Is it the only way to solve this with a case function? Or is there a possibility to store a string in a variable which can be used as a reference to the correct array?

Because I have many clients (50+) I'm searching for a dynamic way to solve this...

Instead of dynamic variables use __subarrays__. – u_mulder Sep 28 '17 at 07:21 — u_mulder, Sep 28 '17 at 07:21

score 2 · Answer 1 · answered Sep 28 '17 at 07:17

2

You were missing few things one of them is _ with in the string.

Try sample code here

Change this to:

$data_array = '$array_data'.$client;

This:

$data_array = ${'array_data_' . $client};

answered Sep 28 '17 at 07:17

Sahil Gulati

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Code Lღver · Accepted Answer · 2017-09-28T07:26:54.353

1

You can achieve this by using following code:

$str = "array_data_".$client;
$data_array = $$str;

Here is the documentation.

edited Sep 28 '17 at 07:26

answered Sep 28 '17 at 07:19

Code Lღver

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How to make a "reference" to an array by string in php

2 Answers2